LinkedIn Queens #892 Answer & Hints – October 9, 2026
Independent walkthrough by Queens Gamers · · 8×8 · Play on LinkedIn
LinkedIn Queens hints and the full solution for puzzle #892 on October 9, 2026. Follow 16 verified deductions on this 8×8 board, starting with row 1.
Region 1 (4 cells) · Region 2 (12 cells) · Region 3 (4 cells) · Region 4 (5 cells) · Region 5 (26 cells) · Region 6 (5 cells) · Region 7 (4 cells) · Region 8 (4 cells)
LinkedIn Queens #892 hints
Open one hint at a time. Reveal the full answer only when you are ready.
Hint 1
Start with row 1. Its candidates are R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. Which outside cells conflict with every candidate? Remember that each row, column and region needs exactly one Queen.
Starting board: no deductions applied yet.
Hint 2
Observe: row 1 must contain one Queen, chosen from R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R2C2 conflicts with R1C1, R1C3 through diagonally adjacent cells; with R1C2 through the same column (column 2); with R1C4, R1C5, R1C6, R1C7, R1C8 through the same region (region 2).
Therefore: mark R2C2 ×. Every possible Queen in row 1 rules out these cells.
Board after step 1; earlier deductions are already applied.
Hint 3
Step 1: Observe: row 1 must contain one Queen, chosen from R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R2C2 conflicts with R1C1, R1C3 through diagonally adjacent cells; with R1C2 through the same column (column 2); with R1C4, R1C5, R1C6, R1C7, R1C8 through the same region (region 2).
Therefore: mark R2C2 ×. Every possible Queen in row 1 rules out these cells.
Step 2: Observe: row 5 must contain one Queen, chosen from R5C1, R5C2, R5C3, R5C4, R5C5, R5C6, R5C7, R5C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R8C8 conflicts with R5C1, R5C2, R5C3, R5C4, R5C5, R5C6, R5C7 through the same region (region 5); with R5C8 through the same column (column 8).
Therefore: mark R8C8 ×. Every possible Queen in row 5 rules out these cells.
Step 3: Observe: row 6 must contain one Queen, chosen from R6C1, R6C2, R6C3, R6C4, R6C5, R6C6, R6C7, R6C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R5C7 conflicts with R6C1, R6C2, R6C3, R6C4, R6C5 through the same region (region 5); with R6C6, R6C8 through diagonally adjacent cells; with R6C7 through the same column (column 7). R7C7 conflicts with R6C1, R6C2, R6C3, R6C4, R6C5 through the same region (region 5); with R6C6, R6C8 through diagonally adjacent cells; with R6C7 through the same column (column 7).
Therefore: mark R5C7, R7C7 ×. Every possible Queen in row 6 rules out these cells.
Step 4: Observe: row 8 must contain one Queen, chosen from R8C1, R8C2, R8C3, R8C4, R8C5, R8C6, R8C7.
Rule: Queens cannot share a row, column or region, or touch diagonally. R5C1 conflicts with R8C1 through the same column (column 1); with R8C2, R8C3, R8C4, R8C5, R8C6, R8C7 through the same region (region 5). R6C1 conflicts with R8C1 through the same column (column 1); with R8C2, R8C3, R8C4, R8C5, R8C6, R8C7 through the same region (region 5).
Therefore: mark R5C1, R6C1 ×. Every possible Queen in row 8 rules out these cells.
Step 5: Observe: region 3 must contain one Queen, chosen from R2C6, R2C7, R2C8, R3C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R3C7 conflicts with R2C6, R2C8 through diagonally adjacent cells; with R2C7 through the same column (column 7); with R3C8 through the same row (row 3).
Therefore: mark R3C7 ×. Every possible Queen in region 3 rules out these cells.
Step 6: Observe: region 8 must contain one Queen, chosen from R7C1, R7C2, R7C3, R8C1.
Rule: Queens cannot share a row, column or region, or touch diagonally. R8C2 conflicts with R7C1, R7C3 through diagonally adjacent cells; with R7C2 through the same column (column 2); with R8C1 through the same row (row 8).
Therefore: mark R8C2 ×. Every possible Queen in region 8 rules out these cells.
Step 7: Observe: row 6 and row 7 and row 8 have remaining candidates R6C2, R6C3, R6C4, R6C5, R6C6, R6C7, R6C8, R7C1, R7C2, R7C3, R7C4, R7C5, R7C6, R7C8, R8C1, R8C3, R8C4, R8C5, R8C6, R8C7, all within region 5 and region 7 and region 8.
Rule: these 3 groups need distinct Queens, filling all 3 target groups.
Therefore: mark R4C2, R4C3, R4C4, R5C2, R5C3, R5C4, R5C5, R5C6 ×. These cells lie outside the groups that reserve those Queens.
Step 8: Observe: row 5 has only one remaining candidate: R5C8.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R5C8. The 10 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 8; earlier deductions are already applied.
Reveal answer
Queens #892 full solution
| Row | Column | Region |
|---|---|---|
| R1 | C3 | 1 |
| R2 | C7 | 3 |
| R3 | C5 | 2 |
| R4 | C1 | 4 |
| R5 | C8 | 6 |
| R6 | C6 | 7 |
| R7 | C2 | 8 |
| R8 | C4 | 5 |
How to solve LinkedIn Queens #892
Step-by-step walkthrough
The key insight
The opening deduction: Observe: row 1 must contain one Queen, chosen from R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R2C2 conflicts with R1C1, R1C3 through diagonally adjacent cells; with R1C2 through the same column (column 2); with R1C4, R1C5, R1C6, R1C7, R1C8 through the same region (region 2).
Therefore: mark R2C2 ×. Every possible Queen in row 1 rules out these cells.
Your solving route
- Steps 1–8: narrow the candidates until R5C8 is forced.
- Steps 9–16: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.
Open each deduction to see the observation, rule and board changes.
Step 1 · Common exclusions
Observe: row 1 must contain one Queen, chosen from R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R2C2 conflicts with R1C1, R1C3 through diagonally adjacent cells; with R1C2 through the same column (column 2); with R1C4, R1C5, R1C6, R1C7, R1C8 through the same region (region 2).
Therefore: mark R2C2 ×. Every possible Queen in row 1 rules out these cells.
Step 2 · Common exclusions
Observe: row 5 must contain one Queen, chosen from R5C1, R5C2, R5C3, R5C4, R5C5, R5C6, R5C7, R5C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R8C8 conflicts with R5C1, R5C2, R5C3, R5C4, R5C5, R5C6, R5C7 through the same region (region 5); with R5C8 through the same column (column 8).
Therefore: mark R8C8 ×. Every possible Queen in row 5 rules out these cells.
Step 3 · Common exclusions
Observe: row 6 must contain one Queen, chosen from R6C1, R6C2, R6C3, R6C4, R6C5, R6C6, R6C7, R6C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R5C7 conflicts with R6C1, R6C2, R6C3, R6C4, R6C5 through the same region (region 5); with R6C6, R6C8 through diagonally adjacent cells; with R6C7 through the same column (column 7). R7C7 conflicts with R6C1, R6C2, R6C3, R6C4, R6C5 through the same region (region 5); with R6C6, R6C8 through diagonally adjacent cells; with R6C7 through the same column (column 7).
Therefore: mark R5C7, R7C7 ×. Every possible Queen in row 6 rules out these cells.
Step 4 · Common exclusions
Observe: row 8 must contain one Queen, chosen from R8C1, R8C2, R8C3, R8C4, R8C5, R8C6, R8C7.
Rule: Queens cannot share a row, column or region, or touch diagonally. R5C1 conflicts with R8C1 through the same column (column 1); with R8C2, R8C3, R8C4, R8C5, R8C6, R8C7 through the same region (region 5). R6C1 conflicts with R8C1 through the same column (column 1); with R8C2, R8C3, R8C4, R8C5, R8C6, R8C7 through the same region (region 5).
Therefore: mark R5C1, R6C1 ×. Every possible Queen in row 8 rules out these cells.
Step 5 · Common exclusions
Observe: region 3 must contain one Queen, chosen from R2C6, R2C7, R2C8, R3C8.
Rule: Queens cannot share a row, column or region, or touch diagonally. R3C7 conflicts with R2C6, R2C8 through diagonally adjacent cells; with R2C7 through the same column (column 7); with R3C8 through the same row (row 3).
Therefore: mark R3C7 ×. Every possible Queen in region 3 rules out these cells.
Step 6 · Common exclusions
Observe: region 8 must contain one Queen, chosen from R7C1, R7C2, R7C3, R8C1.
Rule: Queens cannot share a row, column or region, or touch diagonally. R8C2 conflicts with R7C1, R7C3 through diagonally adjacent cells; with R7C2 through the same column (column 2); with R8C1 through the same row (row 8).
Therefore: mark R8C2 ×. Every possible Queen in region 8 rules out these cells.
Step 7 · Reserved groups
Observe: row 6 and row 7 and row 8 have remaining candidates R6C2, R6C3, R6C4, R6C5, R6C6, R6C7, R6C8, R7C1, R7C2, R7C3, R7C4, R7C5, R7C6, R7C8, R8C1, R8C3, R8C4, R8C5, R8C6, R8C7, all within region 5 and region 7 and region 8.
Rule: these 3 groups need distinct Queens, filling all 3 target groups.
Therefore: mark R4C2, R4C3, R4C4, R5C2, R5C3, R5C4, R5C5, R5C6 ×. These cells lie outside the groups that reserve those Queens.
Step 8 · Only candidate
Observe: row 5 has only one remaining candidate: R5C8.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R5C8. The 10 cells marked × conflict with it by row, column, region or diagonal adjacency.
Step 9 · Only candidate
Observe: row 4 has only one remaining candidate: R4C1.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R4C1. The 8 cells marked × conflict with it by row, column, region or diagonal adjacency.
Step 10 · Only candidate
Observe: region 7 has only one remaining candidate: R6C6.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R6C6. The 10 cells marked × conflict with it by row, column, region or diagonal adjacency.
Step 11 · Only candidate
Observe: row 3 has only one remaining candidate: R3C5.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R3C5. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.
Step 12 · Only candidate
Observe: row 2 has only one remaining candidate: R2C7.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R2C7. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
Step 13 · Locked candidates
Observe: region 8 has 2 remaining candidates: R7C2, R7C3. All lie in row 7.
Rule: region 8 needs one Queen, so it will occupy row 7. row 7 can contain no second Queen outside region 8.
Therefore: mark R7C4 ×.
Step 14 · Only candidate
Observe: column 4 has only one remaining candidate: R8C4.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R8C4. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
Step 15 · Only candidate
Observe: row 7 has only one remaining candidate: R7C2.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R7C2. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
Step 16 · Only candidate
Observe: row 1 has only one remaining candidate: R1C3.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R1C3. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
A tempting mistake
A Queen at R1C1 looks possible before deductions. All 5 terminal branches run out of candidates in region 3, region 2. Rule out this tempting assumption.
Check every branch
Try R7C2.
Try R3C3.
The only candidate in region 2 forces R2C5.
Region 3 has no possible Queen: contradiction.
Try R3C4.
Region 2 has no possible Queen: contradiction.
Try R7C3.
Try R3C2.
Try R2C4.
Region 3 has no possible Queen: contradiction.
Try R2C5.
Region 3 has no possible Queen: contradiction.
Try R3C4.
Region 2 has no possible Queen: contradiction.