LinkedIn Queens #900 Answer & Hints – October 17, 2026
Independent walkthrough by Queens Gamers · · 9×9 · Play on LinkedIn
LinkedIn Queens hints and the full solution for puzzle #900 on October 17, 2026. Follow 20 verified deductions on this 9×9 board, starting with row 1 in region 1.
Region 1 (24 cells) · Region 2 (5 cells) · Region 3 (4 cells) · Region 4 (6 cells) · Region 5 (26 cells) · Region 6 (3 cells) · Region 7 (4 cells) · Region 8 (5 cells) · Region 9 (4 cells)
LinkedIn Queens #900 hints
Open one hint at a time. Reveal the full answer only when you are ready.
Hint 1
Start with row 1. Its candidates are 9 cells (see details). Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.
View 9 coordinate references
Start with row 1. Its candidates are R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8, R1C9. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.
Starting board: no deductions applied yet.
9 cells
R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8, R1C9Hint 2
Observe: row 1 has 9 remaining candidates: 9 cells (see details). All lie in region 1.
View 9 coordinate references
Observe: row 1 has 9 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8, R1C9. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 15 cells (see details) ×.
View 15 coordinate references
Therefore: mark R2C4, R2C5, R2C6, R2C7, R2C8, R2C9, R3C4, R3C5, R3C6, R3C7, R3C8, R3C9, R4C7, R4C8, R4C9 ×.
Board after step 1; earlier deductions are already applied.
9 cells
R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8, R1C915 cells
R2C4, R2C5, R2C6, R2C7, R2C8, R2C9, R3C4, R3C5, R3C6, R3C7, R3C8, R3C9, R4C7, R4C8, R4C9Hint 3
Step 1: Observe: row 1 has 9 remaining candidates: 9 cells (see details). All lie in region 1.
View 9 coordinate references
Step 1: Observe: row 1 has 9 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8, R1C9. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 15 cells (see details) ×.
View 15 coordinate references
Therefore: mark R2C4, R2C5, R2C6, R2C7, R2C8, R2C9, R3C4, R3C5, R3C6, R3C7, R3C8, R3C9, R4C7, R4C8, R4C9 ×.
Step 2: Observe: row 2 has 3 remaining candidates: R2C1, R2C2, R2C3. All lie in region 2.
Rule: row 2 needs one Queen, so it will occupy region 2. region 2 can contain no second Queen outside row 2.
Therefore: mark R3C1, R3C2 ×.
Step 3: Observe: row 3 has only one remaining candidate: R3C3.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R3C3. The 12 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 3; earlier deductions are already applied.
1 cells
R3C313 cells
R1C3, R2C2, R2C3, R3C3, R4C1, R4C2, R4C3, R4C4, R5C3, R6C3, R7C3, R8C3, R9C3Reveal answer
Queens #900 full solution
| Row | Column | Region |
|---|---|---|
| R1 | C4 | 1 |
| R2 | C1 | 2 |
| R3 | C3 | 3 |
| R4 | C6 | 4 |
| R5 | C8 | 8 |
| R6 | C5 | 6 |
| R7 | C7 | 7 |
| R8 | C9 | 5 |
| R9 | C2 | 9 |
How to solve LinkedIn Queens #900
Step-by-step walkthrough
The key insight
The opening deduction: Observe: row 1 has 9 remaining candidates: 9 cells (see details). All lie in region 1.
View 9 coordinate references
The opening deduction: Observe: row 1 has 9 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8, R1C9. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 15 cells (see details) ×.
View 15 coordinate references
Therefore: mark R2C4, R2C5, R2C6, R2C7, R2C8, R2C9, R3C4, R3C5, R3C6, R3C7, R3C8, R3C9, R4C7, R4C8, R4C9 ×.
Your solving route
- Steps 1–3: narrow the candidates until R3C3 is forced.
- Steps 4–20: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.
Open each deduction to see the observation, rule and board changes.
Step 1 · Locked candidates
Observe: row 1 has 9 remaining candidates: 9 cells (see details). All lie in region 1.
View 9 coordinate references
Observe: row 1 has 9 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8, R1C9. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 15 cells (see details) ×.
View 15 coordinate references
Therefore: mark R2C4, R2C5, R2C6, R2C7, R2C8, R2C9, R3C4, R3C5, R3C6, R3C7, R3C8, R3C9, R4C7, R4C8, R4C9 ×.
9 cells
R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8, R1C915 cells
R2C4, R2C5, R2C6, R2C7, R2C8, R2C9, R3C4, R3C5, R3C6, R3C7, R3C8, R3C9, R4C7, R4C8, R4C9Step 2 · Locked candidates
Observe: row 2 has 3 remaining candidates: R2C1, R2C2, R2C3. All lie in region 2.
Rule: row 2 needs one Queen, so it will occupy region 2. region 2 can contain no second Queen outside row 2.
Therefore: mark R3C1, R3C2 ×.
3 cells
R2C1, R2C2, R2C32 cells
R3C1, R3C2Step 3 · Only candidate
Observe: row 3 has only one remaining candidate: R3C3.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R3C3. The 12 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R3C313 cells
R1C3, R2C2, R2C3, R3C3, R4C1, R4C2, R4C3, R4C4, R5C3, R6C3, R7C3, R8C3, R9C3Step 4 · Only candidate
Observe: row 2 has only one remaining candidate: R2C1.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R2C1. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R2C18 cells
R1C1, R1C2, R2C1, R5C1, R6C1, R7C1, R8C1, R9C1Step 5 · Locked candidates
Observe: row 4 has 2 remaining candidates: R4C5, R4C6. All lie in region 4.
Rule: row 4 needs one Queen, so it will occupy region 4. region 4 can contain no second Queen outside row 4.
Therefore: mark R5C4, R5C6, R6C4 ×.
2 cells
R4C5, R4C63 cells
R5C4, R5C6, R6C4Step 6 · Common exclusions
Observe: row 4 must contain one Queen, chosen from R4C5, R4C6.
Rule: Queens cannot share a row, column or region, or touch diagonally. R5C5 conflicts with R4C5 through the same column (column 5); with R4C6 through diagonally adjacent cells.
Therefore: mark R5C5 ×. Every possible Queen in row 4 rules out these cells.
2 cells
R4C5, R4C61 cells
R5C5Step 7 · Locked candidates
Observe: region 6 has 2 remaining candidates: R6C5, R6C6. All lie in row 6.
Rule: region 6 needs one Queen, so it will occupy row 6. row 6 can contain no second Queen outside region 6.
Therefore: mark R6C2, R6C7, R6C8, R6C9 ×.
2 cells
R6C5, R6C64 cells
R6C2, R6C7, R6C8, R6C9Step 8 · Locked candidates
Observe: region 7 has 2 remaining candidates: R5C7, R7C7. All lie in column 7.
Rule: region 7 needs one Queen, so it will occupy column 7. column 7 can contain no second Queen outside region 7.
Therefore: mark R1C7, R8C7, R9C7 ×.
2 cells
R5C7, R7C73 cells
R1C7, R8C7, R9C7Step 9 · Common exclusions
Observe: row 6 must contain one Queen, chosen from R6C5, R6C6.
Rule: Queens cannot share a row, column or region, or touch diagonally. R7C5 conflicts with R6C5 through the same column (column 5); with R6C6 through diagonally adjacent cells. R7C6 conflicts with R6C5 through diagonally adjacent cells; with R6C6 through the same column (column 6).
Therefore: mark R7C5, R7C6 ×. Every possible Queen in row 6 rules out these cells.
2 cells
R6C5, R6C62 cells
R7C5, R7C6Step 10 · Common exclusions
Observe: row 7 must contain one Queen, chosen from R7C2, R7C4, R7C7, R7C8, R7C9.
Rule: Queens cannot share a row, column or region, or touch diagonally. R8C8 conflicts with R7C2, R7C4 through the same region (region 5); with R7C7, R7C9 through diagonally adjacent cells; with R7C8 through the same column (column 8).
Therefore: mark R8C8 ×. Every possible Queen in row 7 rules out these cells.
5 cells
R7C2, R7C4, R7C7, R7C8, R7C91 cells
R8C8Step 11 · Common exclusions
Observe: row 8 must contain one Queen, chosen from R8C2, R8C4, R8C5, R8C6, R8C9.
Rule: Queens cannot share a row, column or region, or touch diagonally. R7C4 conflicts with 4 cells (see details) through the same region (region 5); with R8C4 through the same column (column 4). R9C4 conflicts with 4 cells (see details) through the same region (region 5); with R8C4 through the same column (column 4). R9C5 conflicts with R8C2, R8C6, R8C9 through the same region (region 5); with R8C4 through diagonally adjacent cells; with R8C5 through the same column (column 5).
View 18 coordinate references
Rule: Queens cannot share a row, column or region, or touch diagonally. R7C4 conflicts with R8C2, R8C5, R8C6, R8C9 through the same region (region 5); with R8C4 through the same column (column 4). R9C4 conflicts with R8C2, R8C5, R8C6, R8C9 through the same region (region 5); with R8C4 through the same column (column 4). R9C5 conflicts with R8C2, R8C6, R8C9 through the same region (region 5); with R8C4 through diagonally adjacent cells; with R8C5 through the same column (column 5).
Therefore: mark R7C4, R9C4, R9C5 ×. Every possible Queen in row 8 rules out these cells.
5 cells
R8C2, R8C4, R8C5, R8C6, R8C93 cells
R7C4, R9C4, R9C5Step 12 · Common exclusions
Observe: row 9 must contain one Queen, chosen from R9C2, R9C6, R9C8, R9C9.
Rule: Queens cannot share a row, column or region, or touch diagonally. R5C2 conflicts with R9C2 through the same column (column 2); with R9C6, R9C8, R9C9 through the same region (region 5). R7C2 conflicts with R9C2 through the same column (column 2); with R9C6, R9C8, R9C9 through the same region (region 5). R8C2 conflicts with R9C2 through the same column (column 2); with R9C6, R9C8, R9C9 through the same region (region 5).
View 15 coordinate references
Rule: Queens cannot share a row, column or region, or touch diagonally. R5C2 conflicts with R9C2 through the same column (column 2); with R9C6, R9C8, R9C9 through the same region (region 5). R7C2 conflicts with R9C2 through the same column (column 2); with R9C6, R9C8, R9C9 through the same region (region 5). R8C2 conflicts with R9C2 through the same column (column 2); with R9C6, R9C8, R9C9 through the same region (region 5).
Therefore: mark R5C2, R7C2, R8C2 ×. Every possible Queen in row 9 rules out these cells.
4 cells
R9C2, R9C6, R9C8, R9C93 cells
R5C2, R7C2, R8C2Step 13 · Only candidate
Observe: column 2 has only one remaining candidate: R9C2.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R9C2. The 4 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R9C25 cells
R8C4, R9C2, R9C6, R9C8, R9C9Step 14 · Only candidate
Observe: column 4 has only one remaining candidate: R1C4.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R1C4. The 4 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R1C45 cells
R1C4, R1C5, R1C6, R1C8, R1C9Step 15 · Locked candidates
Observe: column 8 has 2 remaining candidates: R5C8, R7C8. All lie in region 8.
Rule: column 8 needs one Queen, so it will occupy region 8. region 8 can contain no second Queen outside column 8.
Therefore: mark R5C9, R7C9 ×.
2 cells
R5C8, R7C82 cells
R5C9, R7C9Step 16 · Only candidate
Observe: column 9 has only one remaining candidate: R8C9.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R8C9. The 3 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R8C94 cells
R7C8, R8C5, R8C6, R8C9Step 17 · Only candidate
Observe: row 7 has only one remaining candidate: R7C7.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R7C7. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R7C73 cells
R5C7, R6C6, R7C7Step 18 · Only candidate
Observe: row 5 has only one remaining candidate: R5C8.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R5C8. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R5C81 cells
R5C8Step 19 · Only candidate
Observe: row 6 has only one remaining candidate: R6C5.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R6C5. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R6C52 cells
R4C5, R6C5Step 20 · Only candidate
Observe: row 4 has only one remaining candidate: R4C6.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R4C6. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R4C61 cells
R4C6A tempting mistake
A Queen at R1C1 looks possible before deductions. Following the forced placements leaves row 3 without a possible Queen. Rule out this tempting assumption.
Check every branch
The only candidate in row 2 forces R2C3.
Row 3 has no possible Queen: contradiction.