LinkedIn Queens #909 Answer & Hints – October 26, 2026
Independent walkthrough by Queens Gamers · · 8×8 · Play on LinkedIn
LinkedIn Queens hints and the full solution for puzzle #909 on October 26, 2026. Follow 15 verified deductions on this 8×8 board, starting with region 1 in row 1.
Region 1 (2 cells) · Region 2 (50 cells) · Region 3 (2 cells) · Region 4 (2 cells) · Region 5 (2 cells) · Region 6 (2 cells) · Region 7 (2 cells) · Region 8 (2 cells)
LinkedIn Queens #909 hints
Open one hint at a time. Reveal the full answer only when you are ready.
Hint 1
Start with region 1. Its candidates are R1C1, R1C2. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.
Starting board: no deductions applied yet.
2 cells
R1C1, R1C2Hint 2
Observe: region 1 has 2 remaining candidates: R1C1, R1C2. All lie in row 1.
Rule: region 1 needs one Queen, so it will occupy row 1. row 1 can contain no second Queen outside region 1.
Therefore: mark R1C3, R1C4, R1C5, R1C6, R1C7, R1C8 ×.
Board after step 1; earlier deductions are already applied.
2 cells
R1C1, R1C26 cells
R1C3, R1C4, R1C5, R1C6, R1C7, R1C8Hint 3
Step 1: Observe: region 1 has 2 remaining candidates: R1C1, R1C2. All lie in row 1.
Rule: region 1 needs one Queen, so it will occupy row 1. row 1 can contain no second Queen outside region 1.
Therefore: mark R1C3, R1C4, R1C5, R1C6, R1C7, R1C8 ×.
Step 2: Observe: region 3 has 2 remaining candidates: R2C6, R2C7. All lie in row 2.
Rule: region 3 needs one Queen, so it will occupy row 2. row 2 can contain no second Queen outside region 3.
Therefore: mark R2C1, R2C2, R2C3, R2C4, R2C5, R2C8 ×.
Step 3: Observe: region 4 has 2 remaining candidates: R3C3, R3C4. All lie in row 3.
Rule: region 4 needs one Queen, so it will occupy row 3. row 3 can contain no second Queen outside region 4.
Therefore: mark R3C1, R3C2, R3C5, R3C6, R3C7, R3C8 ×.
Step 4: Observe: region 5 has 2 remaining candidates: R4C5, R4C6. All lie in row 4.
Rule: region 5 needs one Queen, so it will occupy row 4. row 4 can contain no second Queen outside region 5.
Therefore: mark R4C1, R4C2, R4C3, R4C4, R4C7, R4C8 ×.
Step 5: Observe: region 6 has 2 remaining candidates: R5C2, R5C3. All lie in row 5.
Rule: region 6 needs one Queen, so it will occupy row 5. row 5 can contain no second Queen outside region 6.
Therefore: mark R5C1, R5C4, R5C5, R5C6, R5C7, R5C8 ×.
Step 6: Observe: region 7 has 2 remaining candidates: R6C6, R6C7. All lie in row 6.
Rule: region 7 needs one Queen, so it will occupy row 6. row 6 can contain no second Queen outside region 7.
Therefore: mark R6C1, R6C2, R6C3, R6C4, R6C5, R6C8 ×.
Step 7: Observe: region 8 has 2 remaining candidates: R8C4, R8C5. All lie in row 8.
Rule: region 8 needs one Queen, so it will occupy row 8. row 8 can contain no second Queen outside region 8.
Therefore: mark R8C1, R8C2, R8C3, R8C6, R8C7, R8C8 ×.
Step 8: Observe: column 8 has only one remaining candidate: R7C8.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R7C8. The 8 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 8; earlier deductions are already applied.
1 cells
R7C89 cells
R6C7, R7C1, R7C2, R7C3, R7C4, R7C5, R7C6, R7C7, R7C8Reveal answer
Queens #909 full solution
| Row | Column | Region |
|---|---|---|
| R1 | C1 | 1 |
| R2 | C7 | 3 |
| R3 | C3 | 4 |
| R4 | C5 | 5 |
| R5 | C2 | 6 |
| R6 | C6 | 7 |
| R7 | C8 | 2 |
| R8 | C4 | 8 |
How to solve LinkedIn Queens #909
Step-by-step walkthrough
The key insight
The opening deduction: Observe: region 1 has 2 remaining candidates: R1C1, R1C2. All lie in row 1.
Rule: region 1 needs one Queen, so it will occupy row 1. row 1 can contain no second Queen outside region 1.
Therefore: mark R1C3, R1C4, R1C5, R1C6, R1C7, R1C8 ×.
Your solving route
- Steps 1–8: narrow the candidates until R7C8 is forced.
- Steps 9–15: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.
Open each deduction to see the observation, rule and board changes.
Step 1 · Locked candidates
Observe: region 1 has 2 remaining candidates: R1C1, R1C2. All lie in row 1.
Rule: region 1 needs one Queen, so it will occupy row 1. row 1 can contain no second Queen outside region 1.
Therefore: mark R1C3, R1C4, R1C5, R1C6, R1C7, R1C8 ×.
2 cells
R1C1, R1C26 cells
R1C3, R1C4, R1C5, R1C6, R1C7, R1C8Step 2 · Locked candidates
Observe: region 3 has 2 remaining candidates: R2C6, R2C7. All lie in row 2.
Rule: region 3 needs one Queen, so it will occupy row 2. row 2 can contain no second Queen outside region 3.
Therefore: mark R2C1, R2C2, R2C3, R2C4, R2C5, R2C8 ×.
2 cells
R2C6, R2C76 cells
R2C1, R2C2, R2C3, R2C4, R2C5, R2C8Step 3 · Locked candidates
Observe: region 4 has 2 remaining candidates: R3C3, R3C4. All lie in row 3.
Rule: region 4 needs one Queen, so it will occupy row 3. row 3 can contain no second Queen outside region 4.
Therefore: mark R3C1, R3C2, R3C5, R3C6, R3C7, R3C8 ×.
2 cells
R3C3, R3C46 cells
R3C1, R3C2, R3C5, R3C6, R3C7, R3C8Step 4 · Locked candidates
Observe: region 5 has 2 remaining candidates: R4C5, R4C6. All lie in row 4.
Rule: region 5 needs one Queen, so it will occupy row 4. row 4 can contain no second Queen outside region 5.
Therefore: mark R4C1, R4C2, R4C3, R4C4, R4C7, R4C8 ×.
2 cells
R4C5, R4C66 cells
R4C1, R4C2, R4C3, R4C4, R4C7, R4C8Step 5 · Locked candidates
Observe: region 6 has 2 remaining candidates: R5C2, R5C3. All lie in row 5.
Rule: region 6 needs one Queen, so it will occupy row 5. row 5 can contain no second Queen outside region 6.
Therefore: mark R5C1, R5C4, R5C5, R5C6, R5C7, R5C8 ×.
2 cells
R5C2, R5C36 cells
R5C1, R5C4, R5C5, R5C6, R5C7, R5C8Step 6 · Locked candidates
Observe: region 7 has 2 remaining candidates: R6C6, R6C7. All lie in row 6.
Rule: region 7 needs one Queen, so it will occupy row 6. row 6 can contain no second Queen outside region 7.
Therefore: mark R6C1, R6C2, R6C3, R6C4, R6C5, R6C8 ×.
2 cells
R6C6, R6C76 cells
R6C1, R6C2, R6C3, R6C4, R6C5, R6C8Step 7 · Locked candidates
Observe: region 8 has 2 remaining candidates: R8C4, R8C5. All lie in row 8.
Rule: region 8 needs one Queen, so it will occupy row 8. row 8 can contain no second Queen outside region 8.
Therefore: mark R8C1, R8C2, R8C3, R8C6, R8C7, R8C8 ×.
2 cells
R8C4, R8C56 cells
R8C1, R8C2, R8C3, R8C6, R8C7, R8C8Step 8 · Only candidate
Observe: column 8 has only one remaining candidate: R7C8.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R7C8. The 8 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R7C89 cells
R6C7, R7C1, R7C2, R7C3, R7C4, R7C5, R7C6, R7C7, R7C8Step 9 · Only candidate
Observe: row 6 has only one remaining candidate: R6C6.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R6C6. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R6C63 cells
R2C6, R4C6, R6C6Step 10 · Only candidate
Observe: row 2 has only one remaining candidate: R2C7.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R2C7. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R2C71 cells
R2C7Step 11 · Only candidate
Observe: row 4 has only one remaining candidate: R4C5.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R4C5. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R4C53 cells
R3C4, R4C5, R8C5Step 12 · Only candidate
Observe: row 3 has only one remaining candidate: R3C3.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R3C3. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R3C32 cells
R3C3, R5C3Step 13 · Only candidate
Observe: row 5 has only one remaining candidate: R5C2.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R5C2. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R5C22 cells
R1C2, R5C2Step 14 · Only candidate
Observe: row 1 has only one remaining candidate: R1C1.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R1C1. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R1C11 cells
R1C1Step 15 · Only candidate
Observe: row 8 has only one remaining candidate: R8C4.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R8C4. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R8C41 cells
R8C4A tempting mistake
A Queen at R1C2 looks possible before deductions. Following the forced placements leaves region 7 without a possible Queen. Rule out this tempting assumption.
Check every branch
The only candidate in region 6 forces R5C3.
The only candidate in region 4 forces R3C4.
The only candidate in region 5 forces R4C6.
The only candidate in region 3 forces R2C7.
Region 7 has no possible Queen: contradiction.