LinkedIn Queens #912 Answer & Hints – October 29, 2026
Independent walkthrough by Queens Gamers · · 8×8 · Play on LinkedIn
LinkedIn Queens hints and the full solution for puzzle #912 on October 29, 2026. Follow 12 verified deductions on this 8×8 board, starting with row 1 in region 1.
Region 1 (36 cells) · Region 2 (4 cells) · Region 3 (4 cells) · Region 4 (4 cells) · Region 5 (4 cells) · Region 6 (4 cells) · Region 7 (4 cells) · Region 8 (4 cells)
LinkedIn Queens #912 hints
Open one hint at a time. Reveal the full answer only when you are ready.
Hint 1
Start with row 1. Its candidates are 8 cells (see details). Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.
View 8 coordinate references
Start with row 1. Its candidates are R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.
Starting board: no deductions applied yet.
8 cells
R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8Hint 2
Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.
View 8 coordinate references
Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 28 cells (see details) ×.
View 28 coordinate references
Therefore: mark R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8 ×.
Board after step 1; earlier deductions are already applied.
8 cells
R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C828 cells
R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8Hint 3
Step 1: Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.
View 8 coordinate references
Step 1: Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 28 cells (see details) ×.
View 28 coordinate references
Therefore: mark R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8 ×.
Step 2: Observe: column 8 has only one remaining candidate: R1C8.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R1C8. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 2; earlier deductions are already applied.
1 cells
R1C88 cells
R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8Reveal answer
Queens #912 full solution
| Row | Column | Region |
|---|---|---|
| R1 | C8 | 1 |
| R2 | C4 | 2 |
| R3 | C6 | 4 |
| R4 | C2 | 3 |
| R5 | C7 | 5 |
| R6 | C3 | 6 |
| R7 | C5 | 8 |
| R8 | C1 | 7 |
How to solve LinkedIn Queens #912
Step-by-step walkthrough
The key insight
The opening deduction: Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.
View 8 coordinate references
The opening deduction: Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 28 cells (see details) ×.
View 28 coordinate references
Therefore: mark R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8 ×.
Your solving route
- Steps 1–2: narrow the candidates until R1C8 is forced.
- Steps 3–12: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.
Open each deduction to see the observation, rule and board changes.
Step 1 · Locked candidates
Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.
View 8 coordinate references
Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 28 cells (see details) ×.
View 28 coordinate references
Therefore: mark R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8 ×.
8 cells
R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C828 cells
R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8Step 2 · Only candidate
Observe: column 8 has only one remaining candidate: R1C8.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R1C8. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R1C88 cells
R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8Step 3 · Only candidate
Observe: column 1 has only one remaining candidate: R8C1.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R8C1. The 3 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R8C14 cells
R6C2, R7C2, R8C1, R8C2Step 4 · Locked candidates
Observe: row 2 has 2 remaining candidates: R2C4, R2C5. All lie in region 2.
Rule: row 2 needs one Queen, so it will occupy region 2. region 2 can contain no second Queen outside row 2.
Therefore: mark R3C4, R3C5 ×.
2 cells
R2C4, R2C52 cells
R3C4, R3C5Step 5 · Locked candidates
Observe: row 7 has 2 remaining candidates: R7C4, R7C5. All lie in region 8.
Rule: row 7 needs one Queen, so it will occupy region 8. region 8 can contain no second Queen outside row 7.
Therefore: mark R6C4, R6C5 ×.
2 cells
R7C4, R7C52 cells
R6C4, R6C5Step 6 · Locked candidates
Observe: column 7 has 2 remaining candidates: R4C7, R5C7. All lie in region 5.
Rule: column 7 needs one Queen, so it will occupy region 5. region 5 can contain no second Queen outside column 7.
Therefore: mark R5C6, R6C6 ×.
2 cells
R4C7, R5C72 cells
R5C6, R6C6Step 7 · Only candidate
Observe: row 6 has only one remaining candidate: R6C3.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R6C3. The 6 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R6C37 cells
R3C3, R4C3, R5C2, R5C3, R5C4, R6C3, R7C4Step 8 · Only candidate
Observe: row 3 has only one remaining candidate: R3C6.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R3C6. The 5 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R3C66 cells
R2C5, R3C6, R4C5, R4C6, R4C7, R5C5Step 9 · Only candidate
Observe: row 2 has only one remaining candidate: R2C4.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R2C4. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R2C42 cells
R2C4, R4C4Step 10 · Only candidate
Observe: row 4 has only one remaining candidate: R4C2.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R4C2. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R4C21 cells
R4C2Step 11 · Only candidate
Observe: row 5 has only one remaining candidate: R5C7.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R5C7. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R5C71 cells
R5C7Step 12 · Only candidate
Observe: row 7 has only one remaining candidate: R7C5.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R7C5. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R7C51 cells
R7C5A tempting mistake
A Queen at R1C1 looks possible before deductions. Following the forced placements leaves column 8 without a possible Queen. Rule out this tempting assumption.
Check every branch
Column 8 has no possible Queen: contradiction.