LinkedIn Queens #912 Answer & Hints – October 29, 2026

Independent walkthrough by Queens Gamers · · 8×8 · Play on LinkedIn

LinkedIn Queens hints and the full solution for puzzle #912 on October 29, 2026. Follow 12 verified deductions on this 8×8 board, starting with row 1 in region 1.

Unsolved Queens #912 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells.

Region 1 (36 cells) · Region 2 (4 cells) · Region 3 (4 cells) · Region 4 (4 cells) · Region 5 (4 cells) · Region 6 (4 cells) · Region 7 (4 cells) · Region 8 (4 cells)

LinkedIn Queens #912 hints

Open one hint at a time. Reveal the full answer only when you are ready.

Hint 1

Start with row 1. Its candidates are 8 cells (see details). Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.

View 8 coordinate references

Start with row 1. Its candidates are R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.

Starting board: no deductions applied yet.

Hint 1: starting candidates · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
8 cellsR1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8
Hint 2

Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.

View 8 coordinate references

Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.

Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.

Therefore: mark 28 cells (see details) ×.

View 28 coordinate references

Therefore: mark R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8 ×.

Board after step 1; earlier deductions are already applied.

Hint 2: after step 1 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
8 cellsR1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8
Changed this step (square marker):
28 cellsR2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8
Hint 3

Step 1: Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.

View 8 coordinate references

Step 1: Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.

Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.

Therefore: mark 28 cells (see details) ×.

View 28 coordinate references

Therefore: mark R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8 ×.

Step 2: Observe: column 8 has only one remaining candidate: R1C8.

Rule: every column needs exactly one Queen.

Therefore: place a Queen at R1C8. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 2; earlier deductions are already applied.

Hint 3: after step 2 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR1C8
Changed this step (square marker):
8 cellsR1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8
Reveal answer

Queens #912 full solution

Full solution for LinkedIn Queens #912 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Queens show the complete solution.
Queen coordinates (rows and columns start at 1)
RowColumnRegion
R1C81
R2C42
R3C64
R4C23
R5C75
R6C36
R7C58
R8C17
How to solve LinkedIn Queens #912

Step-by-step walkthrough

The key insight

The opening deduction: Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.

View 8 coordinate references

The opening deduction: Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.

Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.

Therefore: mark 28 cells (see details) ×.

View 28 coordinate references

Therefore: mark R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8 ×.

Your solving route

  1. Steps 1–2: narrow the candidates until R1C8 is forced.
  2. Steps 3–12: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.

Open each deduction to see the observation, rule and board changes.

Step 1 · Locked candidates

Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.

View 8 coordinate references

Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.

Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.

Therefore: mark 28 cells (see details) ×.

View 28 coordinate references

Therefore: mark R2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8 ×.

Board after step 1 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
8 cellsR1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8
Changed this step (square marker):
28 cellsR2C1, R2C2, R2C3, R2C6, R2C7, R2C8, R3C1, R3C2, R3C7, R3C8, R4C1, R4C8, R5C1, R5C8, R6C1, R6C7, R6C8, R7C1, R7C3, R7C6, R7C7, R7C8, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8
Step 2 · Only candidate

Observe: column 8 has only one remaining candidate: R1C8.

Rule: every column needs exactly one Queen.

Therefore: place a Queen at R1C8. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 2 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR1C8
Changed this step (square marker):
8 cellsR1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8
Step 3 · Only candidate

Observe: column 1 has only one remaining candidate: R8C1.

Rule: every column needs exactly one Queen.

Therefore: place a Queen at R8C1. The 3 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 3 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR8C1
Changed this step (square marker):
4 cellsR6C2, R7C2, R8C1, R8C2
Step 4 · Locked candidates

Observe: row 2 has 2 remaining candidates: R2C4, R2C5. All lie in region 2.

Rule: row 2 needs one Queen, so it will occupy region 2. region 2 can contain no second Queen outside row 2.

Therefore: mark R3C4, R3C5 ×.

Board after step 4 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
2 cellsR2C4, R2C5
Changed this step (square marker):
2 cellsR3C4, R3C5
Step 5 · Locked candidates

Observe: row 7 has 2 remaining candidates: R7C4, R7C5. All lie in region 8.

Rule: row 7 needs one Queen, so it will occupy region 8. region 8 can contain no second Queen outside row 7.

Therefore: mark R6C4, R6C5 ×.

Board after step 5 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
2 cellsR7C4, R7C5
Changed this step (square marker):
2 cellsR6C4, R6C5
Step 6 · Locked candidates

Observe: column 7 has 2 remaining candidates: R4C7, R5C7. All lie in region 5.

Rule: column 7 needs one Queen, so it will occupy region 5. region 5 can contain no second Queen outside column 7.

Therefore: mark R5C6, R6C6 ×.

Board after step 6 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
2 cellsR4C7, R5C7
Changed this step (square marker):
2 cellsR5C6, R6C6
Step 7 · Only candidate

Observe: row 6 has only one remaining candidate: R6C3.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R6C3. The 6 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 7 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR6C3
Changed this step (square marker):
7 cellsR3C3, R4C3, R5C2, R5C3, R5C4, R6C3, R7C4
Step 8 · Only candidate

Observe: row 3 has only one remaining candidate: R3C6.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R3C6. The 5 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 8 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR3C6
Changed this step (square marker):
6 cellsR2C5, R3C6, R4C5, R4C6, R4C7, R5C5
Step 9 · Only candidate

Observe: row 2 has only one remaining candidate: R2C4.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R2C4. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 9 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR2C4
Changed this step (square marker):
2 cellsR2C4, R4C4
Step 10 · Only candidate

Observe: row 4 has only one remaining candidate: R4C2.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R4C2. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 10 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR4C2
Changed this step (square marker):
1 cellsR4C2
Step 11 · Only candidate

Observe: row 5 has only one remaining candidate: R5C7.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R5C7. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 11 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR5C7
Changed this step (square marker):
1 cellsR5C7
Step 12 · Only candidate

Observe: row 7 has only one remaining candidate: R7C5.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R7C5. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 12 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Queens show the complete solution. Reasoning basis (round marker):
1 cellsR7C5
Changed this step (square marker):
1 cellsR7C5

A tempting mistake

A Queen at R1C1 looks possible before deductions. Following the forced placements leaves column 8 without a possible Queen. Rule out this tempting assumption.

Check every branch

Column 8 has no possible Queen: contradiction.

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