Queens Gamers

LinkedIn Queens #895 Answer & Hints – October 12, 2026

Independent walkthrough by Queens Gamers · · 7×7 · Play on LinkedIn

LinkedIn Queens hints and the full solution for puzzle #895 on October 12, 2026. Follow 10 verified deductions on this 7×7 board, starting with region 7 in row 7.

Unsolved Queens #895 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells.

Region 1 (12 cells) · Region 2 (8 cells) · Region 3 (7 cells) · Region 4 (6 cells) · Region 5 (6 cells) · Region 6 (5 cells) · Region 7 (5 cells)

LinkedIn Queens #895 hints

Open one hint at a time. Reveal the full answer only when you are ready.

Hint 1

Start with region 7. Its candidates are R7C1, R7C2, R7C3, R7C4, R7C5. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.

Starting board: no deductions applied yet.

Hint 1: starting candidates · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
5 cellsR7C1, R7C2, R7C3, R7C4, R7C5
Hint 2

Observe: region 7 has 5 remaining candidates: R7C1, R7C2, R7C3, R7C4, R7C5. All lie in row 7.

Rule: region 7 needs one Queen, so it will occupy row 7. row 7 can contain no second Queen outside region 7.

Therefore: mark R7C6, R7C7 ×.

Board after step 1; earlier deductions are already applied.

Hint 2: after step 1 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
5 cellsR7C1, R7C2, R7C3, R7C4, R7C5
 Changed this step (square marker):
2 cellsR7C6, R7C7
Hint 3

Step 1: Observe: region 7 has 5 remaining candidates: R7C1, R7C2, R7C3, R7C4, R7C5. All lie in row 7.

Rule: region 7 needs one Queen, so it will occupy row 7. row 7 can contain no second Queen outside region 7.

Therefore: mark R7C6, R7C7 ×.

Step 2: Observe: region 6 has 3 remaining candidates: R6C5, R6C6, R6C7. All lie in row 6.

Rule: region 6 needs one Queen, so it will occupy row 6. row 6 can contain no second Queen outside region 6.

Therefore: mark R6C1, R6C2, R6C3, R6C4 ×.

Step 3: Observe: region 5 has 2 remaining candidates: R5C1, R5C2. All lie in row 5.

Rule: region 5 needs one Queen, so it will occupy row 5. row 5 can contain no second Queen outside region 5.

Therefore: mark R5C3, R5C4, R5C5, R5C6, R5C7 ×.

Step 4: Observe: region 4 has only one remaining candidate: R4C7.

Rule: every region needs exactly one Queen.

Therefore: place a Queen at R4C7. The 11 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 4; earlier deductions are already applied.

Hint 3: after step 4 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR4C7
 Changed this step (square marker):
12 cellsR1C7, R2C7, R3C6, R3C7, R4C1, R4C2, R4C3, R4C4, R4C5, R4C6, R4C7, R6C7
Reveal answer

Queens #895 full solution

Full solution for LinkedIn Queens #895 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Queens show the complete solution.
Queen coordinates (rows and columns start at 1)
RowColumnRegion
R1C41
R2C62
R3C13
R4C74
R5C25
R6C56
R7C37
How to solve LinkedIn Queens #895

Step-by-step walkthrough

The key insight

The opening deduction: Observe: region 7 has 5 remaining candidates: R7C1, R7C2, R7C3, R7C4, R7C5. All lie in row 7.

Rule: region 7 needs one Queen, so it will occupy row 7. row 7 can contain no second Queen outside region 7.

Therefore: mark R7C6, R7C7 ×.

Your solving route

  1. Steps 1–4: narrow the candidates until R4C7 is forced.
  2. Steps 5–10: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.

Open each deduction to see the observation, rule and board changes.

Step 1 · Locked candidates

Observe: region 7 has 5 remaining candidates: R7C1, R7C2, R7C3, R7C4, R7C5. All lie in row 7.

Rule: region 7 needs one Queen, so it will occupy row 7. row 7 can contain no second Queen outside region 7.

Therefore: mark R7C6, R7C7 ×.

Board after step 1 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
5 cellsR7C1, R7C2, R7C3, R7C4, R7C5
 Changed this step (square marker):
2 cellsR7C6, R7C7
Step 2 · Locked candidates

Observe: region 6 has 3 remaining candidates: R6C5, R6C6, R6C7. All lie in row 6.

Rule: region 6 needs one Queen, so it will occupy row 6. row 6 can contain no second Queen outside region 6.

Therefore: mark R6C1, R6C2, R6C3, R6C4 ×.

Board after step 2 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
3 cellsR6C5, R6C6, R6C7
 Changed this step (square marker):
4 cellsR6C1, R6C2, R6C3, R6C4
Step 3 · Locked candidates

Observe: region 5 has 2 remaining candidates: R5C1, R5C2. All lie in row 5.

Rule: region 5 needs one Queen, so it will occupy row 5. row 5 can contain no second Queen outside region 5.

Therefore: mark R5C3, R5C4, R5C5, R5C6, R5C7 ×.

Board after step 3 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
2 cellsR5C1, R5C2
 Changed this step (square marker):
5 cellsR5C3, R5C4, R5C5, R5C6, R5C7
Step 4 · Only candidate

Observe: region 4 has only one remaining candidate: R4C7.

Rule: every region needs exactly one Queen.

Therefore: place a Queen at R4C7. The 11 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 4 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR4C7
 Changed this step (square marker):
12 cellsR1C7, R2C7, R3C6, R3C7, R4C1, R4C2, R4C3, R4C4, R4C5, R4C6, R4C7, R6C7
Step 5 · Only candidate

Observe: region 3 has only one remaining candidate: R3C1.

Rule: every region needs exactly one Queen.

Therefore: place a Queen at R3C1. The 9 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 5 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR3C1
 Changed this step (square marker):
10 cellsR1C1, R2C1, R2C2, R3C1, R3C2, R3C3, R3C4, R3C5, R5C1, R7C1
Step 6 · Only candidate

Observe: row 5 has only one remaining candidate: R5C2.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R5C2. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 6 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR5C2
 Changed this step (square marker):
3 cellsR1C2, R5C2, R7C2
Step 7 · Only candidate

Observe: region 2 has only one remaining candidate: R2C6.

Rule: every region needs exactly one Queen.

Therefore: place a Queen at R2C6. The 6 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 7 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR2C6
 Changed this step (square marker):
7 cellsR1C5, R1C6, R2C3, R2C4, R2C5, R2C6, R6C6
Step 8 · Only candidate

Observe: row 6 has only one remaining candidate: R6C5.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R6C5. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 8 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR6C5
 Changed this step (square marker):
3 cellsR6C5, R7C4, R7C5
Step 9 · Only candidate

Observe: row 7 has only one remaining candidate: R7C3.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R7C3. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 9 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR7C3
 Changed this step (square marker):
2 cellsR1C3, R7C3
Step 10 · Only candidate

Observe: row 1 has only one remaining candidate: R1C4.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R1C4. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 10 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Queens show the complete solution. Reasoning basis (round marker):
1 cellsR1C4
 Changed this step (square marker):
1 cellsR1C4

A tempting mistake

A Queen at R1C1 looks possible before deductions. All 2 terminal branches run out of candidates in row 3. Rule out this tempting assumption.

Check every branch

  1. Try R2C6.

    Row 3 has no possible Queen: contradiction.

  2. Try R2C7.

    Row 3 has no possible Queen: contradiction.

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