LinkedIn Queens #896 Answer & Hints – October 13, 2026
Independent walkthrough by Queens Gamers · · 9×9 · Play on LinkedIn
LinkedIn Queens hints and the full solution for puzzle #896 on October 13, 2026. Follow 13 verified deductions on this 9×9 board, starting with region 6 in column 1.
Region 1 (4 cells) · Region 2 (56 cells) · Region 3 (3 cells) · Region 4 (3 cells) · Region 5 (3 cells) · Region 6 (2 cells) · Region 7 (3 cells) · Region 8 (3 cells) · Region 9 (4 cells)
LinkedIn Queens #896 hints
Open one hint at a time. Reveal the full answer only when you are ready.
Hint 1
Start with region 6. Its candidates are R5C1, R6C1. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.
Starting board: no deductions applied yet.
2 cells
R5C1, R6C1Hint 2
Observe: region 6 has 2 remaining candidates: R5C1, R6C1. All lie in column 1.
Rule: region 6 needs one Queen, so it will occupy column 1. column 1 can contain no second Queen outside region 6.
Therefore: mark 7 cells (see details) ×.
View 7 coordinate references
Therefore: mark R1C1, R2C1, R3C1, R4C1, R7C1, R8C1, R9C1 ×.
Board after step 1; earlier deductions are already applied.
2 cells
R5C1, R6C17 cells
R1C1, R2C1, R3C1, R4C1, R7C1, R8C1, R9C1Hint 3
Step 1: Observe: region 6 has 2 remaining candidates: R5C1, R6C1. All lie in column 1.
Rule: region 6 needs one Queen, so it will occupy column 1. column 1 can contain no second Queen outside region 6.
Therefore: mark 7 cells (see details) ×.
View 7 coordinate references
Therefore: mark R1C1, R2C1, R3C1, R4C1, R7C1, R8C1, R9C1 ×.
Step 2: Observe: region 1 has 2 remaining candidates: R1C2, R2C2. All lie in column 2.
Rule: region 1 needs one Queen, so it will occupy column 2. column 2 can contain no second Queen outside region 1.
Therefore: mark 7 cells (see details) ×.
View 7 coordinate references
Therefore: mark R3C2, R4C2, R5C2, R6C2, R7C2, R8C2, R9C2 ×.
Step 3: Observe: region 8 has only one remaining candidate: R7C3.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R7C3. The 16 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 3; earlier deductions are already applied.
1 cells
R7C317 cells
R1C3, R2C3, R3C3, R4C3, R5C3, R6C3, R6C4, R7C3, R7C4, R7C5, R7C6, R7C7, R7C8, R7C9, R8C3, R8C4, R9C3Reveal answer
Queens #896 full solution
| Row | Column | Region |
|---|---|---|
| R1 | C2 | 1 |
| R2 | C8 | 3 |
| R3 | C4 | 4 |
| R4 | C6 | 5 |
| R5 | C1 | 6 |
| R6 | C7 | 7 |
| R7 | C3 | 8 |
| R8 | C5 | 9 |
| R9 | C9 | 2 |
How to solve LinkedIn Queens #896
Step-by-step walkthrough
The key insight
The opening deduction: Observe: region 6 has 2 remaining candidates: R5C1, R6C1. All lie in column 1.
Rule: region 6 needs one Queen, so it will occupy column 1. column 1 can contain no second Queen outside region 6.
Therefore: mark 7 cells (see details) ×.
View 7 coordinate references
Therefore: mark R1C1, R2C1, R3C1, R4C1, R7C1, R8C1, R9C1 ×.
Your solving route
- Steps 1–3: narrow the candidates until R7C3 is forced.
- Steps 4–13: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.
Open each deduction to see the observation, rule and board changes.
Step 1 · Locked candidates
Observe: region 6 has 2 remaining candidates: R5C1, R6C1. All lie in column 1.
Rule: region 6 needs one Queen, so it will occupy column 1. column 1 can contain no second Queen outside region 6.
Therefore: mark 7 cells (see details) ×.
View 7 coordinate references
Therefore: mark R1C1, R2C1, R3C1, R4C1, R7C1, R8C1, R9C1 ×.
2 cells
R5C1, R6C17 cells
R1C1, R2C1, R3C1, R4C1, R7C1, R8C1, R9C1Step 2 · Locked candidates
Observe: region 1 has 2 remaining candidates: R1C2, R2C2. All lie in column 2.
Rule: region 1 needs one Queen, so it will occupy column 2. column 2 can contain no second Queen outside region 1.
Therefore: mark 7 cells (see details) ×.
View 7 coordinate references
Therefore: mark R3C2, R4C2, R5C2, R6C2, R7C2, R8C2, R9C2 ×.
2 cells
R1C2, R2C27 cells
R3C2, R4C2, R5C2, R6C2, R7C2, R8C2, R9C2Step 3 · Only candidate
Observe: region 8 has only one remaining candidate: R7C3.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R7C3. The 16 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R7C317 cells
R1C3, R2C3, R3C3, R4C3, R5C3, R6C3, R6C4, R7C3, R7C4, R7C5, R7C6, R7C7, R7C8, R7C9, R8C3, R8C4, R9C3Step 4 · Only candidate
Observe: region 4 has only one remaining candidate: R3C4.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R3C4. The 12 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R3C413 cells
R1C4, R2C4, R2C5, R3C4, R3C5, R3C6, R3C7, R3C8, R3C9, R4C4, R4C5, R5C4, R9C4Step 5 · Only candidate
Observe: region 3 has only one remaining candidate: R2C8.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R2C8. The 12 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R2C813 cells
R1C7, R1C8, R1C9, R2C2, R2C6, R2C7, R2C8, R2C9, R4C8, R5C8, R6C8, R8C8, R9C8Step 6 · Only candidate
Observe: column 2 has only one remaining candidate: R1C2.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R1C2. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R1C23 cells
R1C2, R1C5, R1C6Step 7 · Locked candidates
Observe: region 7 has 2 remaining candidates: R5C7, R6C7. All lie in column 7.
Rule: region 7 needs one Queen, so it will occupy column 7. column 7 can contain no second Queen outside region 7.
Therefore: mark R4C7, R8C7, R9C7 ×.
2 cells
R5C7, R6C73 cells
R4C7, R8C7, R9C7Step 8 · Locked candidates
Observe: region 5 has 2 remaining candidates: R4C6, R5C6. All lie in column 6.
Rule: region 5 needs one Queen, so it will occupy column 6. column 6 can contain no second Queen outside region 5.
Therefore: mark R6C6, R8C6, R9C6 ×.
2 cells
R4C6, R5C63 cells
R6C6, R8C6, R9C6Step 9 · Only candidate
Observe: region 9 has only one remaining candidate: R8C5.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R8C5. The 4 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R8C55 cells
R5C5, R6C5, R8C5, R8C9, R9C5Step 10 · Only candidate
Observe: row 9 has only one remaining candidate: R9C9.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R9C9. The 3 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R9C94 cells
R4C9, R5C9, R6C9, R9C9Step 11 · Only candidate
Observe: row 4 has only one remaining candidate: R4C6.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R4C6. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R4C63 cells
R4C6, R5C6, R5C7Step 12 · Only candidate
Observe: row 5 has only one remaining candidate: R5C1.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R5C1. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R5C12 cells
R5C1, R6C1Step 13 · Only candidate
Observe: row 6 has only one remaining candidate: R6C7.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R6C7. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R6C71 cells
R6C7A tempting mistake
A Queen at R1C1 looks possible before deductions. Following the forced placements leaves region 6 without a possible Queen. Rule out this tempting assumption.
Check every branch
Region 6 has no possible Queen: contradiction.