LinkedIn Queens #897 Answer & Hints – October 14, 2026
Independent walkthrough by Queens Gamers · · 7×7 · Play on LinkedIn
LinkedIn Queens hints and the full solution for puzzle #897 on October 14, 2026. Follow 11 verified deductions on this 7×7 board, starting with region 2 in column 4.
Region 1 (7 cells) · Region 2 (2 cells) · Region 3 (16 cells) · Region 4 (6 cells) · Region 5 (9 cells) · Region 6 (5 cells) · Region 7 (4 cells)
LinkedIn Queens #897 hints
Open one hint at a time. Reveal the full answer only when you are ready.
Hint 1
Start with region 2. Its candidates are R1C4, R2C4. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.
Starting board: no deductions applied yet.
2 cells
R1C4, R2C4Hint 2
Observe: region 2 has 2 remaining candidates: R1C4, R2C4. All lie in column 4.
Rule: region 2 needs one Queen, so it will occupy column 4. column 4 can contain no second Queen outside region 2.
Therefore: mark R3C4, R4C4, R5C4, R6C4, R7C4 ×.
Board after step 1; earlier deductions are already applied.
2 cells
R1C4, R2C45 cells
R3C4, R4C4, R5C4, R6C4, R7C4Hint 3
Step 1: Observe: region 2 has 2 remaining candidates: R1C4, R2C4. All lie in column 4.
Rule: region 2 needs one Queen, so it will occupy column 4. column 4 can contain no second Queen outside region 2.
Therefore: mark R3C4, R4C4, R5C4, R6C4, R7C4 ×.
Step 2: Observe: column 7 has 7 remaining candidates: 7 cells (see details). All lie in region 3.
View 7 coordinate references
Step 2: Observe: column 7 has 7 remaining candidates: R1C7, R2C7, R3C7, R4C7, R5C7, R6C7, R7C7. All lie in region 3.
Rule: column 7 needs one Queen, so it will occupy region 3. region 3 can contain no second Queen outside column 7.
Therefore: mark 9 cells (see details) ×.
View 9 coordinate references
Therefore: mark R1C5, R1C6, R2C6, R3C6, R4C5, R4C6, R5C5, R5C6, R6C6 ×.
Step 3: Observe: column 6 has only one remaining candidate: R7C6.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R7C6. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 3; earlier deductions are already applied.
1 cells
R7C68 cells
R6C5, R6C7, R7C1, R7C2, R7C3, R7C5, R7C6, R7C7Reveal answer
Queens #897 full solution
| Row | Column | Region |
|---|---|---|
| R1 | C4 | 2 |
| R2 | C1 | 1 |
| R3 | C5 | 4 |
| R4 | C3 | 5 |
| R5 | C7 | 3 |
| R6 | C2 | 7 |
| R7 | C6 | 6 |
How to solve LinkedIn Queens #897
Step-by-step walkthrough
The key insight
The opening deduction: Observe: region 2 has 2 remaining candidates: R1C4, R2C4. All lie in column 4.
Rule: region 2 needs one Queen, so it will occupy column 4. column 4 can contain no second Queen outside region 2.
Therefore: mark R3C4, R4C4, R5C4, R6C4, R7C4 ×.
Your solving route
- Steps 1–3: narrow the candidates until R7C6 is forced.
- Steps 4–11: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.
Open each deduction to see the observation, rule and board changes.
Step 1 · Locked candidates
Observe: region 2 has 2 remaining candidates: R1C4, R2C4. All lie in column 4.
Rule: region 2 needs one Queen, so it will occupy column 4. column 4 can contain no second Queen outside region 2.
Therefore: mark R3C4, R4C4, R5C4, R6C4, R7C4 ×.
2 cells
R1C4, R2C45 cells
R3C4, R4C4, R5C4, R6C4, R7C4Step 2 · Locked candidates
Observe: column 7 has 7 remaining candidates: 7 cells (see details). All lie in region 3.
View 7 coordinate references
Observe: column 7 has 7 remaining candidates: R1C7, R2C7, R3C7, R4C7, R5C7, R6C7, R7C7. All lie in region 3.
Rule: column 7 needs one Queen, so it will occupy region 3. region 3 can contain no second Queen outside column 7.
Therefore: mark 9 cells (see details) ×.
View 9 coordinate references
Therefore: mark R1C5, R1C6, R2C6, R3C6, R4C5, R4C6, R5C5, R5C6, R6C6 ×.
7 cells
R1C7, R2C7, R3C7, R4C7, R5C7, R6C7, R7C79 cells
R1C5, R1C6, R2C6, R3C6, R4C5, R4C6, R5C5, R5C6, R6C6Step 3 · Only candidate
Observe: column 6 has only one remaining candidate: R7C6.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R7C6. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R7C68 cells
R6C5, R6C7, R7C1, R7C2, R7C3, R7C5, R7C6, R7C7Step 4 · Only candidate
Observe: region 7 has only one remaining candidate: R6C2.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R6C2. The 9 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R6C210 cells
R1C2, R2C2, R3C2, R4C2, R5C1, R5C2, R5C3, R6C1, R6C2, R6C3Step 5 · Only candidate
Observe: row 5 has only one remaining candidate: R5C7.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R5C7. The 4 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R5C75 cells
R1C7, R2C7, R3C7, R4C7, R5C7Step 6 · Locked candidates
Observe: column 5 has 2 remaining candidates: R2C5, R3C5. All lie in region 4.
Rule: column 5 needs one Queen, so it will occupy region 4. region 4 can contain no second Queen outside column 5.
Therefore: mark R2C3, R3C3 ×.
2 cells
R2C5, R3C52 cells
R2C3, R3C3Step 7 · Common exclusions
Observe: column 4 must contain one Queen, chosen from R1C4, R2C4.
Rule: Queens cannot share a row, column or region, or touch diagonally. R1C3 conflicts with R1C4 through the same row (row 1); with R2C4 through diagonally adjacent cells. R2C5 conflicts with R1C4 through diagonally adjacent cells; with R2C4 through the same row (row 2).
Therefore: mark R1C3, R2C5 ×. Every possible Queen in column 4 rules out these cells.
2 cells
R1C4, R2C42 cells
R1C3, R2C5Step 8 · Only candidate
Observe: column 3 has only one remaining candidate: R4C3.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R4C3. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R4C32 cells
R4C1, R4C3Step 9 · Only candidate
Observe: column 5 has only one remaining candidate: R3C5.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R3C5. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R3C53 cells
R2C4, R3C1, R3C5Step 10 · Only candidate
Observe: row 2 has only one remaining candidate: R2C1.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R2C1. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R2C12 cells
R1C1, R2C1Step 11 · Only candidate
Observe: row 1 has only one remaining candidate: R1C4.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R1C4. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R1C41 cells
R1C4A tempting mistake
A Queen at R1C1 looks possible before deductions. Following the forced placements leaves region 4 without a possible Queen. Rule out this tempting assumption.
Check every branch
The only candidate in region 2 forces R2C4.
Region 4 has no possible Queen: contradiction.