LinkedIn Queens #903 Answer & Hints – October 20, 2026

Independent walkthrough by Queens Gamers · · 8×8 · Play on LinkedIn

LinkedIn Queens hints and the full solution for puzzle #903 on October 20, 2026. Follow 11 verified deductions on this 8×8 board, starting with region 2 in column 6.

Unsolved Queens #903 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells.

Region 1 (41 cells) · Region 2 (2 cells) · Region 3 (2 cells) · Region 4 (2 cells) · Region 5 (2 cells) · Region 6 (10 cells) · Region 7 (2 cells) · Region 8 (3 cells)

LinkedIn Queens #903 hints

Open one hint at a time. Reveal the full answer only when you are ready.

Hint 1

Start with region 2. Its candidates are R1C6, R2C6. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.

Starting board: no deductions applied yet.

Hint 1: starting candidates · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
2 cellsR1C6, R2C6
Hint 2

Observe: region 2 has 2 remaining candidates: R1C6, R2C6. All lie in column 6.

Rule: region 2 needs one Queen, so it will occupy column 6. column 6 can contain no second Queen outside region 2.

Therefore: mark R3C6, R4C6, R5C6, R6C6, R7C6, R8C6 ×.

Board after step 1; earlier deductions are already applied.

Hint 2: after step 1 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
2 cellsR1C6, R2C6
Changed this step (square marker):
6 cellsR3C6, R4C6, R5C6, R6C6, R7C6, R8C6
Hint 3

Step 1: Observe: region 2 has 2 remaining candidates: R1C6, R2C6. All lie in column 6.

Rule: region 2 needs one Queen, so it will occupy column 6. column 6 can contain no second Queen outside region 2.

Therefore: mark R3C6, R4C6, R5C6, R6C6, R7C6, R8C6 ×.

Step 2: Observe: region 3 has 2 remaining candidates: R1C8, R2C8. All lie in column 8.

Rule: region 3 needs one Queen, so it will occupy column 8. column 8 can contain no second Queen outside region 3.

Therefore: mark R3C8, R4C8, R5C8, R6C8, R7C8, R8C8 ×.

Step 3: Observe: region 8 has only one remaining candidate: R8C7.

Rule: every region needs exactly one Queen.

Therefore: place a Queen at R8C7. The 12 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 3; earlier deductions are already applied.

Hint 3: after step 3 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR8C7
Changed this step (square marker):
13 cellsR1C7, R2C7, R3C7, R4C7, R5C7, R6C7, R7C7, R8C1, R8C2, R8C3, R8C4, R8C5, R8C7
Reveal answer

Queens #903 full solution

Full solution for LinkedIn Queens #903 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Queens show the complete solution.
Queen coordinates (rows and columns start at 1)
RowColumnRegion
R1C62
R2C83
R3C51
R4C24
R5C45
R6C16
R7C37
R8C78
How to solve LinkedIn Queens #903

Step-by-step walkthrough

The key insight

The opening deduction: Observe: region 2 has 2 remaining candidates: R1C6, R2C6. All lie in column 6.

Rule: region 2 needs one Queen, so it will occupy column 6. column 6 can contain no second Queen outside region 2.

Therefore: mark R3C6, R4C6, R5C6, R6C6, R7C6, R8C6 ×.

Your solving route

  1. Steps 1–3: narrow the candidates until R8C7 is forced.
  2. Steps 4–11: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.

Open each deduction to see the observation, rule and board changes.

Step 1 · Locked candidates

Observe: region 2 has 2 remaining candidates: R1C6, R2C6. All lie in column 6.

Rule: region 2 needs one Queen, so it will occupy column 6. column 6 can contain no second Queen outside region 2.

Therefore: mark R3C6, R4C6, R5C6, R6C6, R7C6, R8C6 ×.

Board after step 1 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
2 cellsR1C6, R2C6
Changed this step (square marker):
6 cellsR3C6, R4C6, R5C6, R6C6, R7C6, R8C6
Step 2 · Locked candidates

Observe: region 3 has 2 remaining candidates: R1C8, R2C8. All lie in column 8.

Rule: region 3 needs one Queen, so it will occupy column 8. column 8 can contain no second Queen outside region 3.

Therefore: mark R3C8, R4C8, R5C8, R6C8, R7C8, R8C8 ×.

Board after step 2 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
2 cellsR1C8, R2C8
Changed this step (square marker):
6 cellsR3C8, R4C8, R5C8, R6C8, R7C8, R8C8
Step 3 · Only candidate

Observe: region 8 has only one remaining candidate: R8C7.

Rule: every region needs exactly one Queen.

Therefore: place a Queen at R8C7. The 12 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 3 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR8C7
Changed this step (square marker):
13 cellsR1C7, R2C7, R3C7, R4C7, R5C7, R6C7, R7C7, R8C1, R8C2, R8C3, R8C4, R8C5, R8C7
Step 4 · Locked candidates

Observe: region 4 has 2 remaining candidates: R4C2, R5C2. All lie in column 2.

Rule: region 4 needs one Queen, so it will occupy column 2. column 2 can contain no second Queen outside region 4.

Therefore: mark R1C2, R2C2, R3C2, R6C2, R7C2 ×.

Board after step 4 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
2 cellsR4C2, R5C2
Changed this step (square marker):
5 cellsR1C2, R2C2, R3C2, R6C2, R7C2
Step 5 · Only candidate

Observe: region 7 has only one remaining candidate: R7C3.

Rule: every region needs exactly one Queen.

Therefore: place a Queen at R7C3. The 10 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 5 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR7C3
Changed this step (square marker):
11 cellsR1C3, R2C3, R3C3, R4C3, R5C3, R6C3, R6C4, R7C1, R7C3, R7C4, R7C5
Step 6 · Only candidate

Observe: region 6 has only one remaining candidate: R6C1.

Rule: every region needs exactly one Queen.

Therefore: place a Queen at R6C1. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 6 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR6C1
Changed this step (square marker):
8 cellsR1C1, R2C1, R3C1, R4C1, R5C1, R5C2, R6C1, R6C5
Step 7 · Only candidate

Observe: column 2 has only one remaining candidate: R4C2.

Rule: every column needs exactly one Queen.

Therefore: place a Queen at R4C2. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 7 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR4C2
Changed this step (square marker):
3 cellsR4C2, R4C4, R4C5
Step 8 · Only candidate

Observe: region 5 has only one remaining candidate: R5C4.

Rule: every region needs exactly one Queen.

Therefore: place a Queen at R5C4. The 4 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 8 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR5C4
Changed this step (square marker):
5 cellsR1C4, R2C4, R3C4, R5C4, R5C5
Step 9 · Only candidate

Observe: row 3 has only one remaining candidate: R3C5.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R3C5. The 3 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 9 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR3C5
Changed this step (square marker):
4 cellsR1C5, R2C5, R2C6, R3C5
Step 10 · Only candidate

Observe: row 2 has only one remaining candidate: R2C8.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R2C8. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 10 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Dots are candidates, × marks excluded cells. Reasoning basis (round marker):
1 cellsR2C8
Changed this step (square marker):
2 cellsR1C8, R2C8
Step 11 · Only candidate

Observe: row 1 has only one remaining candidate: R1C6.

Rule: every row needs exactly one Queen.

Therefore: place a Queen at R1C6. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.

Board after step 11 · Small cell numbers identify regions. Rows run from top to bottom; columns from left to right. Queens show the complete solution. Reasoning basis (round marker):
1 cellsR1C6
Changed this step (square marker):
1 cellsR1C6

A tempting mistake

A Queen at R1C1 looks possible before deductions. Following the forced placements leaves row 3 without a possible Queen. Rule out this tempting assumption.

Check every branch

Row 3 has no possible Queen: contradiction.

Keep practicing