LinkedIn Queens #903 Answer & Hints – October 20, 2026
Independent walkthrough by Queens Gamers · · 8×8 · Play on LinkedIn
LinkedIn Queens hints and the full solution for puzzle #903 on October 20, 2026. Follow 11 verified deductions on this 8×8 board, starting with region 2 in column 6.
Region 1 (41 cells) · Region 2 (2 cells) · Region 3 (2 cells) · Region 4 (2 cells) · Region 5 (2 cells) · Region 6 (10 cells) · Region 7 (2 cells) · Region 8 (3 cells)
LinkedIn Queens #903 hints
Open one hint at a time. Reveal the full answer only when you are ready.
Hint 1
Start with region 2. Its candidates are R1C6, R2C6. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.
Starting board: no deductions applied yet.
2 cells
R1C6, R2C6Hint 2
Observe: region 2 has 2 remaining candidates: R1C6, R2C6. All lie in column 6.
Rule: region 2 needs one Queen, so it will occupy column 6. column 6 can contain no second Queen outside region 2.
Therefore: mark R3C6, R4C6, R5C6, R6C6, R7C6, R8C6 ×.
Board after step 1; earlier deductions are already applied.
2 cells
R1C6, R2C66 cells
R3C6, R4C6, R5C6, R6C6, R7C6, R8C6Hint 3
Step 1: Observe: region 2 has 2 remaining candidates: R1C6, R2C6. All lie in column 6.
Rule: region 2 needs one Queen, so it will occupy column 6. column 6 can contain no second Queen outside region 2.
Therefore: mark R3C6, R4C6, R5C6, R6C6, R7C6, R8C6 ×.
Step 2: Observe: region 3 has 2 remaining candidates: R1C8, R2C8. All lie in column 8.
Rule: region 3 needs one Queen, so it will occupy column 8. column 8 can contain no second Queen outside region 3.
Therefore: mark R3C8, R4C8, R5C8, R6C8, R7C8, R8C8 ×.
Step 3: Observe: region 8 has only one remaining candidate: R8C7.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R8C7. The 12 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 3; earlier deductions are already applied.
1 cells
R8C713 cells
R1C7, R2C7, R3C7, R4C7, R5C7, R6C7, R7C7, R8C1, R8C2, R8C3, R8C4, R8C5, R8C7Reveal answer
Queens #903 full solution
| Row | Column | Region |
|---|---|---|
| R1 | C6 | 2 |
| R2 | C8 | 3 |
| R3 | C5 | 1 |
| R4 | C2 | 4 |
| R5 | C4 | 5 |
| R6 | C1 | 6 |
| R7 | C3 | 7 |
| R8 | C7 | 8 |
How to solve LinkedIn Queens #903
Step-by-step walkthrough
The key insight
The opening deduction: Observe: region 2 has 2 remaining candidates: R1C6, R2C6. All lie in column 6.
Rule: region 2 needs one Queen, so it will occupy column 6. column 6 can contain no second Queen outside region 2.
Therefore: mark R3C6, R4C6, R5C6, R6C6, R7C6, R8C6 ×.
Your solving route
- Steps 1–3: narrow the candidates until R8C7 is forced.
- Steps 4–11: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.
Open each deduction to see the observation, rule and board changes.
Step 1 · Locked candidates
Observe: region 2 has 2 remaining candidates: R1C6, R2C6. All lie in column 6.
Rule: region 2 needs one Queen, so it will occupy column 6. column 6 can contain no second Queen outside region 2.
Therefore: mark R3C6, R4C6, R5C6, R6C6, R7C6, R8C6 ×.
2 cells
R1C6, R2C66 cells
R3C6, R4C6, R5C6, R6C6, R7C6, R8C6Step 2 · Locked candidates
Observe: region 3 has 2 remaining candidates: R1C8, R2C8. All lie in column 8.
Rule: region 3 needs one Queen, so it will occupy column 8. column 8 can contain no second Queen outside region 3.
Therefore: mark R3C8, R4C8, R5C8, R6C8, R7C8, R8C8 ×.
2 cells
R1C8, R2C86 cells
R3C8, R4C8, R5C8, R6C8, R7C8, R8C8Step 3 · Only candidate
Observe: region 8 has only one remaining candidate: R8C7.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R8C7. The 12 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R8C713 cells
R1C7, R2C7, R3C7, R4C7, R5C7, R6C7, R7C7, R8C1, R8C2, R8C3, R8C4, R8C5, R8C7Step 4 · Locked candidates
Observe: region 4 has 2 remaining candidates: R4C2, R5C2. All lie in column 2.
Rule: region 4 needs one Queen, so it will occupy column 2. column 2 can contain no second Queen outside region 4.
Therefore: mark R1C2, R2C2, R3C2, R6C2, R7C2 ×.
2 cells
R4C2, R5C25 cells
R1C2, R2C2, R3C2, R6C2, R7C2Step 5 · Only candidate
Observe: region 7 has only one remaining candidate: R7C3.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R7C3. The 10 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R7C311 cells
R1C3, R2C3, R3C3, R4C3, R5C3, R6C3, R6C4, R7C1, R7C3, R7C4, R7C5Step 6 · Only candidate
Observe: region 6 has only one remaining candidate: R6C1.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R6C1. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R6C18 cells
R1C1, R2C1, R3C1, R4C1, R5C1, R5C2, R6C1, R6C5Step 7 · Only candidate
Observe: column 2 has only one remaining candidate: R4C2.
Rule: every column needs exactly one Queen.
Therefore: place a Queen at R4C2. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R4C23 cells
R4C2, R4C4, R4C5Step 8 · Only candidate
Observe: region 5 has only one remaining candidate: R5C4.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R5C4. The 4 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R5C45 cells
R1C4, R2C4, R3C4, R5C4, R5C5Step 9 · Only candidate
Observe: row 3 has only one remaining candidate: R3C5.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R3C5. The 3 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R3C54 cells
R1C5, R2C5, R2C6, R3C5Step 10 · Only candidate
Observe: row 2 has only one remaining candidate: R2C8.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R2C8. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R2C82 cells
R1C8, R2C8Step 11 · Only candidate
Observe: row 1 has only one remaining candidate: R1C6.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R1C6. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R1C61 cells
R1C6A tempting mistake
A Queen at R1C1 looks possible before deductions. Following the forced placements leaves row 3 without a possible Queen. Rule out this tempting assumption.
Check every branch
Row 3 has no possible Queen: contradiction.