LinkedIn Queens #904 Answer & Hints – October 21, 2026
Independent walkthrough by Queens Gamers · · 7×7 · Play on LinkedIn
LinkedIn Queens hints and the full solution for puzzle #904 on October 21, 2026. Follow 10 verified deductions on this 7×7 board, starting with region 4.
Region 1 (7 cells) · Region 2 (17 cells) · Region 3 (5 cells) · Region 4 (1 cell) · Region 5 (6 cells) · Region 6 (4 cells) · Region 7 (9 cells)
LinkedIn Queens #904 hints
Open one hint at a time. Reveal the full answer only when you are ready.
Hint 1
Start with region 4. Its candidates are R2C6. Which placement is forced? Remember that each row, column and region needs exactly one Queen.
Starting board: no deductions applied yet.
1 cells
R2C6Hint 2
Observe: region 4 has only one remaining candidate: R2C6.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R2C6. The 16 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 1; earlier deductions are already applied.
1 cells
R2C617 cells
R1C5, R1C6, R1C7, R2C1, R2C2, R2C3, R2C4, R2C5, R2C6, R2C7, R3C5, R3C6, R3C7, R4C6, R5C6, R6C6, R7C6Hint 3
Step 1: Observe: region 4 has only one remaining candidate: R2C6.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R2C6. The 16 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 1; earlier deductions are already applied.
1 cells
R2C617 cells
R1C5, R1C6, R1C7, R2C1, R2C2, R2C3, R2C4, R2C5, R2C6, R2C7, R3C5, R3C6, R3C7, R4C6, R5C6, R6C6, R7C6Reveal answer
Queens #904 full solution
| Row | Column | Region |
|---|---|---|
| R1 | C1 | 1 |
| R2 | C6 | 4 |
| R3 | C4 | 3 |
| R4 | C2 | 6 |
| R5 | C5 | 2 |
| R6 | C3 | 7 |
| R7 | C7 | 5 |
How to solve LinkedIn Queens #904
Step-by-step walkthrough
The key insight
The opening deduction: Observe: region 4 has only one remaining candidate: R2C6.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R2C6. The 16 cells marked × conflict with it by row, column, region or diagonal adjacency.
Your solving route
- Steps 1–1: narrow the candidates until R2C6 is forced.
- Steps 2–10: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.
Open each deduction to see the observation, rule and board changes.
Step 1 · Only candidate
Observe: region 4 has only one remaining candidate: R2C6.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R2C6. The 16 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R2C617 cells
R1C5, R1C6, R1C7, R2C1, R2C2, R2C3, R2C4, R2C5, R2C6, R2C7, R3C5, R3C6, R3C7, R4C6, R5C6, R6C6, R7C6Step 2 · Only candidate
Observe: region 5 has only one remaining candidate: R7C7.
Rule: every region needs exactly one Queen.
Therefore: place a Queen at R7C7. The 8 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R7C79 cells
R4C7, R5C7, R6C7, R7C1, R7C2, R7C3, R7C4, R7C5, R7C7Step 3 · Locked candidates
Observe: region 3 has 2 remaining candidates: R3C4, R4C4. All lie in column 4.
Rule: region 3 needs one Queen, so it will occupy column 4. column 4 can contain no second Queen outside region 3.
Therefore: mark R1C4, R5C4, R6C4 ×.
2 cells
R3C4, R4C43 cells
R1C4, R5C4, R6C4Step 4 · Locked candidates
Observe: region 7 has 3 remaining candidates: R6C1, R6C2, R6C3. All lie in row 6.
Rule: region 7 needs one Queen, so it will occupy row 6. row 6 can contain no second Queen outside region 7.
Therefore: mark R6C5 ×.
3 cells
R6C1, R6C2, R6C31 cells
R6C5Step 5 · Locked candidates
Observe: column 5 has 2 remaining candidates: R4C5, R5C5. All lie in region 2.
Rule: column 5 needs one Queen, so it will occupy region 2. region 2 can contain no second Queen outside column 5.
Therefore: mark R1C2, R1C3 ×.
2 cells
R4C5, R5C52 cells
R1C2, R1C3Step 6 · Only candidate
Observe: row 1 has only one remaining candidate: R1C1.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R1C1. The 7 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R1C18 cells
R1C1, R3C1, R3C2, R3C3, R4C1, R4C3, R5C1, R6C1Step 7 · Only candidate
Observe: row 3 has only one remaining candidate: R3C4.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R3C4. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R3C43 cells
R3C4, R4C4, R4C5Step 8 · Only candidate
Observe: row 4 has only one remaining candidate: R4C2.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R4C2. The 3 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R4C24 cells
R4C2, R5C2, R5C3, R6C2Step 9 · Only candidate
Observe: row 5 has only one remaining candidate: R5C5.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R5C5. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R5C51 cells
R5C5Step 10 · Only candidate
Observe: row 6 has only one remaining candidate: R6C3.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R6C3. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R6C31 cells
R6C3A tempting mistake
A Queen at R1C2 looks possible before deductions. Following the forced placements leaves column 5 without a possible Queen. Rule out this tempting assumption.
Check every branch
Column 5 has no possible Queen: contradiction.