LinkedIn Queens #905 Answer & Hints – October 22, 2026
Independent walkthrough by Queens Gamers · · 8×8 · Play on LinkedIn
LinkedIn Queens hints and the full solution for puzzle #905 on October 22, 2026. Follow 14 verified deductions on this 8×8 board, starting with region 4 in row 3.
Region 1 (16 cells) · Region 2 (10 cells) · Region 3 (6 cells) · Region 4 (2 cells) · Region 5 (6 cells) · Region 6 (15 cells) · Region 7 (4 cells) · Region 8 (5 cells)
LinkedIn Queens #905 hints
Open one hint at a time. Reveal the full answer only when you are ready.
Hint 1
Start with region 4. Its candidates are R3C5, R3C6. Can you spot a shared row, column or region? Remember that each row, column and region needs exactly one Queen.
Starting board: no deductions applied yet.
2 cells
R3C5, R3C6Hint 2
Observe: region 4 has 2 remaining candidates: R3C5, R3C6. All lie in row 3.
Rule: region 4 needs one Queen, so it will occupy row 3. row 3 can contain no second Queen outside region 4.
Therefore: mark R3C1, R3C2, R3C3, R3C4, R3C7, R3C8 ×.
Board after step 1; earlier deductions are already applied.
2 cells
R3C5, R3C66 cells
R3C1, R3C2, R3C3, R3C4, R3C7, R3C8Hint 3
Step 1: Observe: region 4 has 2 remaining candidates: R3C5, R3C6. All lie in row 3.
Rule: region 4 needs one Queen, so it will occupy row 3. row 3 can contain no second Queen outside region 4.
Therefore: mark R3C1, R3C2, R3C3, R3C4, R3C7, R3C8 ×.
Step 2: Observe: region 8 has 5 remaining candidates: R7C3, R7C4, R7C5, R7C6, R7C7. All lie in row 7.
Rule: region 8 needs one Queen, so it will occupy row 7. row 7 can contain no second Queen outside region 8.
Therefore: mark R7C1, R7C2, R7C8 ×.
Step 3: Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.
View 8 coordinate references
Step 3: Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 7 cells (see details) ×.
View 7 coordinate references
Therefore: mark R2C1, R2C2, R2C3, R2C4, R2C8, R4C1, R4C2 ×.
Step 4: Observe: row 2 has 3 remaining candidates: R2C5, R2C6, R2C7. All lie in region 2.
Rule: row 2 needs one Queen, so it will occupy region 2. region 2 can contain no second Queen outside row 2.
Therefore: mark R4C6, R4C7, R4C8, R5C7, R5C8 ×.
Step 5: Observe: row 8 has 8 remaining candidates: 8 cells (see details). All lie in region 6.
View 8 coordinate references
Step 5: Observe: row 8 has 8 remaining candidates: R8C1, R8C2, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8. All lie in region 6.
Rule: row 8 needs one Queen, so it will occupy region 6. region 6 can contain no second Queen outside row 8.
Therefore: mark R5C1, R5C2, R6C1, R6C8 ×.
Step 6: Observe: row 2 must contain one Queen, chosen from R2C5, R2C6, R2C7.
Rule: Queens cannot share a row, column or region, or touch diagonally. R1C6 conflicts with R2C5, R2C7 through diagonally adjacent cells; with R2C6 through the same column (column 6). R3C6 conflicts with R2C5, R2C7 through diagonally adjacent cells; with R2C6 through the same column (column 6).
View 8 coordinate references
Rule: Queens cannot share a row, column or region, or touch diagonally. R1C6 conflicts with R2C5, R2C7 through diagonally adjacent cells; with R2C6 through the same column (column 6). R3C6 conflicts with R2C5, R2C7 through diagonally adjacent cells; with R2C6 through the same column (column 6).
Therefore: mark R1C6, R3C6 ×. Every possible Queen in row 2 rules out these cells.
Step 7: Observe: row 3 has only one remaining candidate: R3C5.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R3C5. The 9 cells marked × conflict with it by row, column, region or diagonal adjacency.
Board after step 7; earlier deductions are already applied.
1 cells
R3C510 cells
R1C5, R2C5, R2C6, R3C5, R4C4, R4C5, R5C5, R6C5, R7C5, R8C5Reveal answer
Queens #905 full solution
| Row | Column | Region |
|---|---|---|
| R1 | C1 | 1 |
| R2 | C7 | 2 |
| R3 | C5 | 4 |
| R4 | C3 | 3 |
| R5 | C6 | 5 |
| R6 | C2 | 7 |
| R7 | C4 | 8 |
| R8 | C8 | 6 |
How to solve LinkedIn Queens #905
Step-by-step walkthrough
The key insight
The opening deduction: Observe: region 4 has 2 remaining candidates: R3C5, R3C6. All lie in row 3.
Rule: region 4 needs one Queen, so it will occupy row 3. row 3 can contain no second Queen outside region 4.
Therefore: mark R3C1, R3C2, R3C3, R3C4, R3C7, R3C8 ×.
Your solving route
- Steps 1–7: narrow the candidates until R3C5 is forced.
- Steps 8–14: use the confirmed Queens to eliminate conflicts, then repeat the deductions for the remaining regions.
Open each deduction to see the observation, rule and board changes.
Step 1 · Locked candidates
Observe: region 4 has 2 remaining candidates: R3C5, R3C6. All lie in row 3.
Rule: region 4 needs one Queen, so it will occupy row 3. row 3 can contain no second Queen outside region 4.
Therefore: mark R3C1, R3C2, R3C3, R3C4, R3C7, R3C8 ×.
2 cells
R3C5, R3C66 cells
R3C1, R3C2, R3C3, R3C4, R3C7, R3C8Step 2 · Locked candidates
Observe: region 8 has 5 remaining candidates: R7C3, R7C4, R7C5, R7C6, R7C7. All lie in row 7.
Rule: region 8 needs one Queen, so it will occupy row 7. row 7 can contain no second Queen outside region 8.
Therefore: mark R7C1, R7C2, R7C8 ×.
5 cells
R7C3, R7C4, R7C5, R7C6, R7C73 cells
R7C1, R7C2, R7C8Step 3 · Locked candidates
Observe: row 1 has 8 remaining candidates: 8 cells (see details). All lie in region 1.
View 8 coordinate references
Observe: row 1 has 8 remaining candidates: R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C8. All lie in region 1.
Rule: row 1 needs one Queen, so it will occupy region 1. region 1 can contain no second Queen outside row 1.
Therefore: mark 7 cells (see details) ×.
View 7 coordinate references
Therefore: mark R2C1, R2C2, R2C3, R2C4, R2C8, R4C1, R4C2 ×.
8 cells
R1C1, R1C2, R1C3, R1C4, R1C5, R1C6, R1C7, R1C87 cells
R2C1, R2C2, R2C3, R2C4, R2C8, R4C1, R4C2Step 4 · Locked candidates
Observe: row 2 has 3 remaining candidates: R2C5, R2C6, R2C7. All lie in region 2.
Rule: row 2 needs one Queen, so it will occupy region 2. region 2 can contain no second Queen outside row 2.
Therefore: mark R4C6, R4C7, R4C8, R5C7, R5C8 ×.
3 cells
R2C5, R2C6, R2C75 cells
R4C6, R4C7, R4C8, R5C7, R5C8Step 5 · Locked candidates
Observe: row 8 has 8 remaining candidates: 8 cells (see details). All lie in region 6.
View 8 coordinate references
Observe: row 8 has 8 remaining candidates: R8C1, R8C2, R8C3, R8C4, R8C5, R8C6, R8C7, R8C8. All lie in region 6.
Rule: row 8 needs one Queen, so it will occupy region 6. region 6 can contain no second Queen outside row 8.
Therefore: mark R5C1, R5C2, R6C1, R6C8 ×.
8 cells
R8C1, R8C2, R8C3, R8C4, R8C5, R8C6, R8C7, R8C84 cells
R5C1, R5C2, R6C1, R6C8Step 6 · Common exclusions
Observe: row 2 must contain one Queen, chosen from R2C5, R2C6, R2C7.
Rule: Queens cannot share a row, column or region, or touch diagonally. R1C6 conflicts with R2C5, R2C7 through diagonally adjacent cells; with R2C6 through the same column (column 6). R3C6 conflicts with R2C5, R2C7 through diagonally adjacent cells; with R2C6 through the same column (column 6).
View 8 coordinate references
Rule: Queens cannot share a row, column or region, or touch diagonally. R1C6 conflicts with R2C5, R2C7 through diagonally adjacent cells; with R2C6 through the same column (column 6). R3C6 conflicts with R2C5, R2C7 through diagonally adjacent cells; with R2C6 through the same column (column 6).
Therefore: mark R1C6, R3C6 ×. Every possible Queen in row 2 rules out these cells.
3 cells
R2C5, R2C6, R2C72 cells
R1C6, R3C6Step 7 · Only candidate
Observe: row 3 has only one remaining candidate: R3C5.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R3C5. The 9 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R3C510 cells
R1C5, R2C5, R2C6, R3C5, R4C4, R4C5, R5C5, R6C5, R7C5, R8C5Step 8 · Only candidate
Observe: row 2 has only one remaining candidate: R2C7.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R2C7. The 5 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R2C76 cells
R1C7, R1C8, R2C7, R6C7, R7C7, R8C7Step 9 · Only candidate
Observe: row 4 has only one remaining candidate: R4C3.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R4C3. The 6 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R4C37 cells
R1C3, R4C3, R5C3, R5C4, R6C3, R7C3, R8C3Step 10 · Only candidate
Observe: row 5 has only one remaining candidate: R5C6.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R5C6. The 3 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R5C64 cells
R5C6, R6C6, R7C6, R8C6Step 11 · Only candidate
Observe: row 7 has only one remaining candidate: R7C4.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R7C4. The 3 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R7C44 cells
R1C4, R6C4, R7C4, R8C4Step 12 · Only candidate
Observe: row 6 has only one remaining candidate: R6C2.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R6C2. The 2 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R6C23 cells
R1C2, R6C2, R8C2Step 13 · Only candidate
Observe: row 1 has only one remaining candidate: R1C1.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R1C1. The 1 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R1C12 cells
R1C1, R8C1Step 14 · Only candidate
Observe: row 8 has only one remaining candidate: R8C8.
Rule: every row needs exactly one Queen.
Therefore: place a Queen at R8C8. The 0 cells marked × conflict with it by row, column, region or diagonal adjacency.
1 cells
R8C81 cells
R8C8A tempting mistake
A Queen at R1C2 looks possible before deductions. All 2 terminal branches run out of candidates in region 8, row 2. Rule out this tempting assumption.
Check every branch
Try R3C5.
The only candidate in row 2 forces R2C7.
The only candidate in row 4 forces R4C3.
The only candidate in region 7 forces R6C4.
The only candidate in region 5 forces R5C6.
Region 8 has no possible Queen: contradiction.
Try R3C6.
Row 2 has no possible Queen: contradiction.